Add the duplicate in another list

Solution for Add the duplicate in another list
is Given Below:

I want to place the duplicates from one list in another list. In the follow example, I am attempting to create a list red_dup that contains every item that contains a ‘red’ id that is duplicated. Similarly, I want to do the same for each food in a food_dup list.

What I have:

values = [[1, 'red1', 'food4'], [1, 'red2', 'food4'], [1, 'red1', 'food9']]

The result I’m looking for:

red_dup = [[1, 'red1', 'food4'], [1, 'red1', 'food9']]
food_dup = [[1, 'red1', 'food4'], [1, 'red2', 'food4']]

In my code the “values” comes from a generator function from a class.

The function returns these values.

The 1 is the distance, and the red or blue is the entity distance from the food.

This is what code returns. The red underline is a X, Y coordinates.

you can use dict to store and filter for dupe values

from collections import defaultdict
res = defaultdict(list)
for item in values:
    _, color, food = item 
    res[color].append(item)
    res[food].append(item)
    

[v for v in res.values() if len(v) > 1]

result:

[[[1, 'red1', 'food4'], [1, 'red1', 'food9']],
 [[1, 'red1', 'food4'], [1, 'red2', 'food4']]]

Here is my suggestion:

values = [[1, 'red1', 'food4'], [1, 'red2', 'food4'], [1, 'red1', 'food9']]

red_dup = []
food_dup = []

for i in values:
    red=[k for k in values if k[1]==i[1]]
    if len(red)>1:
        red_dup.extend(red)
    food = [k for k in values if k[2]==i[2]]
    if len(food)>1:
        food_dup.extend(food)

red_dup=sorted(red_dup, key=lambda x: [x[1], x[2]])[::2]
food_dup=sorted(food_dup, key=lambda x: [x[2], x[1]])[::2]

>>>print(red_dup)
#[[1, 'red1', 'food4'], [1, 'red1', 'food9']]
>>>print(food_dup)
#[[1, 'red1', 'food4'], [1, 'red2', 'food4']]