# How do i return more than one result from this if the input have similar value

Solution for How do i return more than one result from this if the input have similar value
is Given Below:

E.g.: In this scenario, most expensive items are needed.

``````d= (('Shirts',40000),('trousers',40000),('provisions',34000),('others',34000))

def pick_the_most_expensive_from_my_list(d):
material=""
price = None
for x,y in d:
if price is None:
price= y
material= x
while y > price:
price = y
material= x

return material,price
``````

You could find the max price first, then return pairs that have that price.

``````d= (('Shirts',40000),('trousers',40000),('provisions',34000),('others',34000))

def pick_the_most_expensive_from_my_list(d):
return [pair for pair in d if pair[1]==max([item[1] for item in d])]
``````

Output

``````[('Shirts', 40000), ('trousers', 40000)]
``````

you need to find the maximum price first and then filter the value having that much price.

``````d= (('Shirts',40000),('trousers',40000),('provisions',34000),('others',34000))

def pick_the_most_expensive_from_my_list(d):
if not d:
return None
max_v = max(d, key=lambda x:x[1])[-1]
return list(filter(lambda x: x[1]==max_v, d))

print(pick_the_most_expensive_from_my_list(d))
``````

output

``````[('Shirts', 40000), ('trousers', 40000)]
``````

or using dictionary

``````d= (('Shirts',40000),('trousers',40000),('provisions',34000),('others',34000))

def pick_the_most_expensive_from_my_list(d):
if not d:
return None
price = {}

for i in d:
if i[1] not in price:
price[i[1]] = [i]
else:
price[i[1]].append(i)

return price.get(max(price))

print(list(pick_the_most_expensive_from_my_list(d)))
``````

``````
def mostExpensiveItems():
items = ['']
prices = [0]
for currentItems, currentPrices in items:
if currentPrices > prices[-1]:
items.append(currentItems)
prices.append(currentPrices)
elif currentPrices == prices[-1]:
items.append(currentItems)
prices.append(currentPrices)
print(items)
print(prices)
``````