Is it possible to get ASCII font bitmap array just from a binary number?

Solution for Is it possible to get ASCII font bitmap array just from a binary number?
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I’m looking for a solution where I can generate a 6*8 bitmap just from a binary number.

Assume that you were given the char A which is binary 0b01000001. Is it possible for you to create a 6*8 bitmap (two colors only 0 and 1) from the letter A in C?

Or do I need to have a character set list such as this to find how the bitmap should be shaped?

enter image description here

Of course you have to form a character map for each character.

Yet code can reflect your font design, tedious, but kinda fun.

#define MAP(s) ((s[0]=='*')<<5 | (s[1]=='*')<<4 | (s[2]=='*')<<3 | 
                (s[3]=='*')<<2 | (s[4]=='*')<<1 | (s[5]=='*')<<0)
static const unsigned char map[256][8] = {
  // ...
  // 2 examples
  // A
  { MAP( "  *** "),
    MAP( " *   *"),
    MAP( " *   *"),
    MAP( " *****"),
    MAP( " *   *"),
    MAP( " *   *"),
    MAP( " *   *"),
    MAP( "      ") },
    // B
  { MAP( " **** "),
    MAP( " *   *"),
    MAP( " *   *"),
    MAP( " ****"),
    MAP( " *   *"),
    MAP( " *   *"),
    MAP( " **** "),
    MAP( "      ") },
    // ...
};

Various macros can wrap the intialization in an alternate manner as needed.